Light-refraction law: relative indexes of refraction
$$\frac{sin(\alpha)}{sin(\gamma)} = \frac{n2}{n1}$$
α - incidence angle
γ - refraction angle
n1, n2 - absolute indexes of refraction in environments
γ - refraction angle
n1, n2 - absolute indexes of refraction in environments
Find
It is known that:
= 