Calculation: ryCIzK - 1
2* h* n* cos(β) =
k* λ
k* λ
|
2* h* n* cos(β) = k* λ$$2\cdot h\cdot n\cdot cos(\beta)$$ = $$k\cdot \lambda$$
h =
$$h$$ = $$\frac{k\cdot \lambda}{2\cdot n\cdot cos(\beta)}$$
| k* λ |
| / 2/ n/ cos(β) |
h =
$$h$$ = $$\frac{0.5\cdot k\cdot \lambda}{cos(\beta)\cdot n}$$
| 0.5* k* λ |
| / cos(β)/ n |