Calculation: X2lJxB - 1
tan(φ) =
| (X_L-X_C) |
| / R |
|
tan(φ) =
$$tan(\phi)$$ = $$\frac{X_{L}-X_{C}}{R}$$
| (X_L-X_C) |
| / R |
tan(φ) =
-
$$tan(\phi)$$ = $$\frac{X_{L}}{R}-\frac{X_{C}}{R}$$
| X_L |
| / R |
| X_C |
| / R |
φ = arctan((
-
))$$\phi$$ = $$arctan((\frac{X_{L}}{R}-\frac{X_{C}}{R}))$$
| X_L |
| / R |
| X_C |
| / R |
φ = arctan(
-
)$$\phi$$ = $$arctan(\frac{X_{L}}{R}-\frac{X_{C}}{R})$$
| X_L |
| / R |
| X_C |
| / R |