Calculation: ON9sRG - 1
a^3+ b^3 =
(a+b)* ( a^2+ a* b+ b^2)
(a+b)* ( a^2+ a* b+ b^2)
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a^3+ b^3 = (a+b)* ( a^2+ a* b+ b^2)$$a^{3}+b^{3}$$ = $$(a+b)\cdot (a^{2}+a\cdot b+b^{2})$$
a^3- (a+b)* ( a^2+ a* b+ b^2) = - b^3$$a^{3}-(a+b)\cdot (a^{2}+a\cdot b+b^{2})$$ = $$-b^{3}$$
- 2* a^2* b- 2* a* b^2- b^3 = - b^3$$-2\cdot a^{2}\cdot b-2\cdot a\cdot b^{2}-b^{3}$$ = $$-b^{3}$$
a = 0$$a$$ = $$0$$